3x^2-24x-540=0

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Solution for 3x^2-24x-540=0 equation: 



3x^2-24x-540=0

a = 3; b = -24; c = -540;
Δ = b2-4ac
Δ = -242-4·3·(-540)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-84}{2*3}=\frac{-60}{6}
=-10
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+84}{2*3}=\frac{108}{6}
=18
$

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